Re: 10 amp booster Re: DCC Wiring - Can it cause a fire?
V = I * R
Ohms law re-writen to solve for ohms
R = V / I
The equation is setup like this:
Ohms(Wiring) = V(track) / I(booster)
For the 10Amp booster, I(booster) = 10A and Vtrack = 16V (Factory setting)
Ohms = 16V / 10A = 1.6 Ohms per advertised specifications.
However in practice the 10Amp booster puts out close to 12Amps (Production design margin to guarantee 10amps) which mean the actual real value is closer to 1.3 Ohms.
This is the maximum resistance value one can tolerated from one track terminal on the booster out and around the layout all the back to the other terminal of the same booster. Your layout wiring should make sure it is less than this value. Hence the quarter test does just that. If a short circuit between the rails does not shutdown the booster, you have a wiring problem with to much resistance which in this case means you have more than 1.3 Ohms.
On Jan 22, 2014, at 7:00 AM, madog wrote:
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