
Digit sums 9 messages
Hi All Here is some interesting things to examine. We all know that if the digit sum of a number is 9 then the number is divisible by 9. So 0% of these numbers are prime But what if the digit sum is 8
Hi All Here is some interesting things to examine. We all know that if the digit sum of a number is 9 then the number is divisible by 9. So 0% of these numbers are prime But what if the digit sum is 8

By kimowww
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RFDS prize quiz contest 2 messages
If you’re reading this, I really hope you will enter my new highIQlike quiz contest. For two reasons: first, there is a significant cash prize (US$100) for the winner; and second, and more important
If you’re reading this, I really hope you will enter my new highIQlike quiz contest. For two reasons: first, there is a significant cash prize (US$100) for the winner; and second, and more important

By Tim Roberts
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Probability that n random walks (1D) intersect a single point 16 messages
Hello, Last weeks I did an analysis on the intersection of nrandom walks in a single point. There are quit some new (to me) observations I made. A short question is posted on mathematics stacks excha
Hello, Last weeks I did an analysis on the intersection of nrandom walks in a single point. There are quit some new (to me) observations I made. A short question is posted on mathematics stacks excha

By OOOVincentOOO
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Formula for number of coprimes in 2N interval
Hi All I wonder if there exist a formula that can calculate the number of coprimes in a 2N interval by using the positions of the primes. One could use a empirical approach to this problem. Suppose th
Hi All I wonder if there exist a formula that can calculate the number of coprimes in a 2N interval by using the positions of the primes. One could use a empirical approach to this problem. Suppose th

By kimowww
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Factoring large difficulttofactor positive integers
Thank you, Tim. I see from the smallest three numbers that you posted that none of my own constructed factoring algorithms can compete with Pollard Rho for factoring the large difficulttofactor posi
Thank you, Tim. I see from the smallest three numbers that you posted that none of my own constructed factoring algorithms can compete with Pollard Rho for factoring the large difficulttofactor posi

By Kermit Rose
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factorization 2 messages
Hi all, I've been asked by a correspondent for some large numbers that can be used to test their factorization method. This may be useful to others in this group, so here are a few I've concocted: 723
Hi all, I've been asked by a correspondent for some large numbers that can be used to test their factorization method. This may be useful to others in this group, so here are a few I've concocted: 723

By Tim Roberts
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THE ORANGE THEORY  Mathematical Calculations of Odds and Index of Coincidences needed
This is a report on the constant patterning of use of a specific ciphertext strand and template that holds for the Z340 and other ciphers in the mix Included is the use of the steganography of Pi in t
This is a report on the constant patterning of use of a specific ciphertext strand and template that holds for the Z340 and other ciphers in the mix Included is the use of the steganography of Pi in t

By Eldorado
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Difficulty of factoring positive integers
Currently, I expect the difficulty, in general, of factoring an odd positive integer to be proportional to the cube of its logarithm. Kermit
Currently, I expect the difficulty, in general, of factoring an odd positive integer to be proportional to the cube of its logarithm. Kermit

By Kermit Rose
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Circle from ngon circumference=1
Hello, Usually when determining pi a circle is drawn with a radius, then polygons are inscribed and out scribed. Lasts months I attempted to find a more intuitive way explaining the irrational and tra
Hello, Usually when determining pi a circle is drawn with a radius, then polygons are inscribed and out scribed. Lasts months I attempted to find a more intuitive way explaining the irrational and tra

By OOOVincentOOO
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Something interesting 2 messages
Hi All Here is something, I find interesting. It looks like the following is true with some exceptions : Let N^2<N^2+r<(N+1)^2 then (N+k)^2+r+k is either prime ( possibly it is only coprime with the p
Hi All Here is something, I find interesting. It looks like the following is true with some exceptions : Let N^2<N^2+r<(N+1)^2 then (N+k)^2+r+k is either prime ( possibly it is only coprime with the p

By kimowww
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Integer solutions to these equations 5 messages
Hi All I wonder if it is possible to find the integer solutions to diophantine equations of this form : Z=N*(2x+1)((N+1+2x)/2)*y Example : N=5 Z=5*(2x+1)((6+2x)/2)*y=10x+53yx*y I want to find all
Hi All I wonder if it is possible to find the integer solutions to diophantine equations of this form : Z=N*(2x+1)((N+1+2x)/2)*y Example : N=5 Z=5*(2x+1)((6+2x)/2)*y=10x+53yx*y I want to find all

By kimowww
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How efficient would this factoring algorithm be for factoring large integers? 5 messages
How efficient would this factoring algorithm be for factoring large integers? z = 33 (z1) = 32 t1 *(t1 * t2 * t3 + t2 + t3) = 32 t1 = 2 (t1*t2*t3 + t2 + t3) = 16 (2*t2*t3+t2+t3)=16 t2 and t3 are same
How efficient would this factoring algorithm be for factoring large integers? z = 33 (z1) = 32 t1 *(t1 * t2 * t3 + t2 + t3) = 32 t1 = 2 (t1*t2*t3 + t2 + t3) = 16 (2*t2*t3+t2+t3)=16 t2 and t3 are same

By Kermit Rose
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An illustration of the complicated relationship between addition and multiplication. 9 messages
An illustration of the complicated relationship between addition and multiplication. 10*30 + 1*10 + 1*30 +1*1 = 341 10*29 +2*10 + 1*29 + 1*2 = 341 9*30 + 1*9 + 2*30 +2*1 = 341 10*28 + 3*10 + 1*28 +1*3
An illustration of the complicated relationship between addition and multiplication. 10*30 + 1*10 + 1*30 +1*1 = 341 10*29 +2*10 + 1*29 + 1*2 = 341 9*30 + 1*9 + 2*30 +2*1 = 341 10*28 + 3*10 + 1*28 +1*3

By Kermit Rose
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An interesting identity 6 messages
An interesting identity: ((x−a)(x−b)) / ((c−a)(c−b)) + ((x−b)(x−c)) / ((a−b)(a−c)) + ((x−c)(x−a)) / ((b−c)(b−a))=1
An interesting identity: ((x−a)(x−b)) / ((c−a)(c−b)) + ((x−b)(x−c)) / ((a−b)(a−c)) + ((x−c)(x−a)) / ((b−c)(b−a))=1

By Kermit Rose
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Proposed partial proof of the binary Goldbach conjecture
Dear colleagues, Attached is my manuscript containing a proposed partial proof of the binary Goldbach conjecture. Your constructive comments are most welcome. Best regards, Tatenda Kubalalika.
Dear colleagues, Attached is my manuscript containing a proposed partial proof of the binary Goldbach conjecture. Your constructive comments are most welcome. Best regards, Tatenda Kubalalika.

By tatendakubalalika@...
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FW: Testing my factoring of integers program
>>> z=(z1)*53*59+1 >>> Factor2021(z) x = 277 y = 6941373105249865123 z = 1922760350154212639071 Number of iterations = 2 Probable Prime Test Algorithm Factor, using base, 3 >>> z=(z1)*61*67+1 >>> Fa
>>> z=(z1)*53*59+1 >>> Factor2021(z) x = 277 y = 6941373105249865123 z = 1922760350154212639071 Number of iterations = 2 Probable Prime Test Algorithm Factor, using base, 3 >>> z=(z1)*61*67+1 >>> Fa

By Kermit Rose
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Testing my factoring of integers program
Yesterday, I thought of this "square root algorithm", but the test shows that it is not as good as the older probable prime test factor algorithm. >>> z=2*3*5*7*11*13*17*19+1 >>> Factor2021(z) x = 347
Yesterday, I thought of this "square root algorithm", but the test shows that it is not as good as the older probable prime test factor algorithm. >>> z=2*3*5*7*11*13*17*19+1 >>> Factor2021(z) x = 347

By Kermit Rose
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Problem in algebra 11 messages
I'm having difficulty expanding the following expression I want to write it as a 4th degree polynomial in y1 so that I can take the next step of assigning functional values to y1 that will make z2^2 a
I'm having difficulty expanding the following expression I want to write it as a 4th degree polynomial in y1 so that I can take the next step of assigning functional values to y1 that will make z2^2 a

By Kermit Rose
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3x3 magic square of squares solved (without graphics or spheres): 9 messages
take the perfect solution: abc def ghi which yields (f.p.p) : 2e = c + g [0] The perfect solution above can be rewritten: bac hgi edf which yields 2g = c+e [1] subtracting [0] & [1] toget
take the perfect solution: abc def ghi which yields (f.p.p) : 2e = c + g [0] The perfect solution above can be rewritten: bac hgi edf which yields 2g = c+e [1] subtracting [0] & [1] toget

By Conor Williams
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An Inequality related to Legendre conjecture 2 messages
Hi All I hope someone will help me out here. Legendre conjecture is true if this is true (see attachment). This involves a summation series, which is using Ln(N). Kim
Hi All I hope someone will help me out here. Legendre conjecture is true if this is true (see attachment). This involves a summation series, which is using Ln(N). Kim

By kimowww
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