toggle quoted messageShow quoted text
Probably because it gives maximum distance rather than maximum signal.
? ? ? ? ...
On Tue, 19 May 2020 at 14:21, Phil Guttridge G3TCU <p.guttridge@...
So why does Airscout suggest the optimum place for a plane is mid
way on the path then? And that seems to work in practice, if you're
ever lucky enough to have a plane flying exactly along the path.
I'm aware there are special cases, like when one station is in a
valley and can only 'see' the plane when it's pretty close.
I assume an aircraft must be a form of passive reflector or is there
a difference between aircraft *scatter* and a passive repeater that
is a deliberate reflector?
Thanks & 73, Phil G3TCU
On 19/05/2020 12:11, Andy G4JNT via
repeater is exactly on the direct line from Tx to Rx, MAXIMUM
loss occurs if it is placed mid way
to have it close to one end or the other
for a simplistic view will follow shortly
feel a spreadsheet coming on ..
to recall doing this calculation back in the dim and
distant past for work, and IIRC the mid point gave
furthest range extension. But that would have been for a
naval scenario and no hills !
On Tue, 19 May 2020 at
10:58, Iain Young <g7iii@...
On 19/05/20 10:24, Nick Gregory G0HIK via groups.io wrote:
> I have been told that you cant have the passive
repeater anywhere near
> the middle of the link and has to be right at one end
of it. Not sure
> how the logic works, as several of the communities
fed by these are not
> that close to them, say up to 2 to 5 miles away.
I beg to differ. While this was done on 144MHz, and
433MHz, last time I
checked the rules of physics don't change at 1.2GHz and
up,so here are
a couple of links tto a presentation that I did based on
an experiment a
couple of years ago:
Personally, I think it's all about overcoming the extra
path loss, so
you need gain in the antennas. I must try it on 23cms and