Re: Questions on impedance matching
Yes I agree, with 600 ohms attached the terminal voltage is the nominal value, with opentoggle quoted messageShow quoted text
circuit it is double.
In audio we NEVER match source and load impedances, not with small signals nor with
power amplifiers and loudspeakers. The universal system comprises low source impedances
and high load impedances, ratios of 1:10 to 1:1000 are common.
Things are happening in audio at such a slow speed that reflected energy is irrelevant.
Reflections don't cause "distortion" in audio. Distortion in audio occurs due to non-linearity in
the amplification and from abuse of amplification by the connection of load impedances
below the rated value.
ratio of two voltages expressed in dB is 20 times the log base10 of the ratio
in round numbers:
double is +6dB
half is -6dB
3x is +10dB
10x is +20dB
100x is +40dB
ratio of two powers expressed in dB is 10 times the log base 10 of the ratio
in round numbers:
double is +3dB
half is -3dB
10x is +10dB
100x is +20dB
Hope this helps
On 12 Feb 2018 at 6:34, David Berlind wrote:
thank you @tedR: when you say "if it (the 600 ohms) is absent," you actually mean if there's
no load at all. Because, according to the math, other loads (above or below 600 ohms)
should not necessarily yield double the voltage. It will be somewhere in between. I'm trying to
understand the use cases for where maximum power transfer (watts) trumps maximum
voltage (amplitude) and vice versa. My assumption is that as you move off the maximum
power transfer point (where impedances match), you get signal distortion due to refection
and at that point, maximizing voltage means you're just maximizing a distorted signal which is
not helpful in radio or cable communications, but might be desirable in audio. The
relationship to dB is a new dimension for me. What's the math behind any dB calculations
and what is optimal? What dB am I shooting for?