Yes, you have it right.
For a given sound pressure into the mike,
the -24 dB mike creates a voltage that is 10 times bigger than the -44 dB mike.
A 10 times bigger voltage into a fixed resistance means 100 times more power,
since power in watts = volts * amps = volts * volts/ohms.
With 100 times more power, that's 10 * log(100) = 20 dB more power.
If the mike were zero dB, we'd get 1 volt from the mike.
Since the voltages we are dealing with are less than one volt,
we get negative numbers when representing the values in dB.
On Mon, Jul 16, 2018 at 04:58 PM, iz oos wrote:
. . .
So, would - 24db be 20db more sensitive than - 44db?
0 dB = 1 volt per Pascal
-24dB = .0.063 V/Pa
-44 db = 0.0063 V/Pa